factorize 64m^3+343n^3
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Answer:
Step-by-step explanation:
(4m-7m)[16m²+28mn+49n²]
Explanation:
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We know the algebraic identity:
a³-b³ = (a-b)(a²+ab+b²)
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Given
64m³ - 343n³
= (4m)³ - (7n)³
= (4m-7m)[(4m)²+(4m)(7n)+(7n)²]
= (4m-7m)[16m²+28mn+49n²]
Therefore,
64m³-343n³
= (4m-7m)[16m²+28mn+49n²]
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