Question

factorize 6ab - b^2 + 12ac - 2bc

Answer 1

6ab - b² + 12ac -2bc

b (6a-b) +2c (6a-b)

(b+2c) (6a-b) ANS..

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Answer 2

Given:

6ab - b² + 12ac - 2bc

Solution:

6ab - b² + 12ac - 2bc

Grouping the given equation:

(6ab - b²) + (12ac - 2bc)

Taking b common from the first group:

b (6a - b) + (12ac - 2bc)

Taking 2c common from the second group:

b (6a - b) + 2c (6a - b)

(6a - b) (b + 2c)

Hence, the answer is (6a - b) (b + 2c)