Math, asked by alokmondal1105, 9 months ago

Factorize:
6i)
(p+q)^2 -20 (p+q) -125

Answers

Answered by devraaz170

Step-by-step explanation:

${(p + q)}^{2} - 20(p + q) - 125 \\ = {(p + q)}^{2} - 25(p + q) + 5(p + q) - 125 \\ = (p + q)(p + q - 25) + 5(p + q - 25) \\ = (p + q - 25)(p + q + 5)$

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Factorize: 6i) (p+q)^2 -20 (p+q) -125

Answers

Factorize:
6i)
(p+q)^2 -20 (p+q) -125