Math, asked by sanjanareddy37, 10 months ago

FACTORIZE 6x2 - 17 x - 3 = 0 *

Answers

Answered by TheValkyrie

$6 {x}^{2} - 18x + x - 3 = 0$

$6x(x - 3) + 1(x - 3) = 0$

$(x - 3)(6x + 1) = 0$

$x - 3 = 0 \\ x = 3$

$6x + 1 = x = \frac{ - 1}{6}$

Answered by Anonymous

Answer:

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Factoring 6x2-7x-3

The first term is, 6x2 its coefficient is 6 .

The middle term is, -7x its coefficient is -7 .

The last term, "the constant", is -3

Step-1 : Multiply the coefficient of the first term by the constant 6 • -3 = -18

Step-2 : Find two factors of -18 whose sum equals the coefficient of the middle term, which is -7 .

-18 + 1 = -17

-9 + 2 = -7 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and 2

6x2 - 9x + 2x - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

3x • (2x-3)

Add up the last 2 terms, pulling out common factors :

1 • (2x-3)

Step-5 : Add up the four terms of step 4 :

(3x+1) • (2x-3)

Which is the desired factorization

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