Question

Factorize
6x² - x-2
please answer​

Answer 1

Answer:

6x^2 - 4x + 3x - 2

2x ( 3x - 2 ) + 1 ( 3x - 2 )

( 3x - 2 ) ( 2x + 1 )

Answer 2

Let's use the AC Method.

First multiply the coefficient ( A = 6 ) of the  x 2  term by the coefficient ( C = 2 ) of the constant term - ignoring the sign.

A C= 6 ⋅ 2 = 12

Notice that the sign of the constant ( C ) term is negative.

According to the AC Method, we need to look for a factorisation of our  

A

C

value into a pair of factors, whose difference is the middle coefficient

B = 1 .

Well  

4 × 3 = 12  and 4− 3 = 1 .

So the pair we want is  4  and  3 .

Now use this pair to split the middle term then factor by grouping:

6 x 2− x −2

= 6 x 2 − 4 x + 3 x − 2

= ( 6 x 2 − 4 x) + ( 3 x − 2 )  

= 2 x ( 3 x − 2 ) + ( 3 x − 2 )

= ( 2 x − 1 ) ( 3 x− 2 )

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