factorize 7√3x^2 +10x+√3
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the answer is -√3/7 and -√3/3
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Question :--- Factorize 7√3x² + 10x + √3 .
Formula used :--
→ put the Given Equation to 0 .
→ Sridharacharya formula for Solving Quadratic Equation ax² +bx + c = 0 says that,
→ x = [ -b±√(b²-4ac) / 2a ]
or,
→ x = [ - b± √D /2a ] where D(Discriminant)= b²-4ac
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Solution :---
Given Equation is 7√3x² + 10x + √3.
we have ,
→ a = 7√3
→ b = 10
→ c = √3
Putting values we get,
→ D = b² - 4ac
→ D = (10)² - 4*7√3*√3
→ D = 100 - 4*7*3
→ D = 100 - 84
→ D = 16
Putting this value in formula now , we get,
→ x = -b ± √D/2a
→ x = (-10 ± √16) / (2*7√3)
→ x = (-10±4) / 14√3
→ x = (-10+4)/14√3 or, (-10-4)/14√3
→ x = (-6)/14√3 or , (-14)/14√3
→ x = (-3)/7√3 , or , (-1)/√3 .
Now, Rationalizing both values we get,
→ x = (-3/7√3) * (√3/√3)
→ x = (-3√3)/(7√3*√3)
→ x = (-3√3)/21
→ x = (-√3)/7
Or,
→ x = (-1/√3) * (√3/√3)
→ x = (-√3)/(√3*√3)
→ x = (-√3)/3
Hence, x € { (-√3)/7 , (-√3)/3 }
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