Question

Factorize 7(5a-3)²-14(5a-3)
pls help​

Answer 1

Step-by-step explanation:

Given, f(a)= 5a3 + 11a2 + 4a –2

In f(a) putting a=±1, ±2, ±3, we see for which value of a, f(a)=0

f(−1)=5.(−1)3+11.(−1)2+4.(−1)−2=0

We observe that f(−1) = 0

From factor theorem, we can say, (a+1) is a factor of f(a)

5a3 + 11a2 + 4a –2 = 5a3 + 11a2 + 4a –2

= 5a3+5a2+6a2+6a−2a−2

= 5a2(a+1)+6a(a+1)−2(a+1)

= (a+1)(5a2+6a−2)

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Answer 2

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