Question

factorize 7(p+2) ²-8(p+2)​

Answer 1

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7(p + 2)² - 8(p + 2) = 0

=> 7( p² + 4 + 4p) - 8(p + 2) = 0

=> 7p² + 28 + 28p - 8p - 16 = 0

=> 7p² - 20p + 12 = 0

=> 7p² - 14p - 6p + 12 = 0

=> 7p(p - 2) - 6(p - 2) = 0

=> (p - 2)(7p - 6) = 0

So :

$p = 2 \\ \\ or \\ \\ p = \frac{6}{7}$

$\huge\pink{\mid{\fbox{\tt{Thanks❤}}\mid}}$

Answer 2

Answer:-

7(p + 2)² - 8(p + 2) = 0

=> 7( p² + 4 + 4p) - 8(p + 2) = 0

=> 7p² + 28 + 28p - 8p - 16 = 0

=> 7p² - 20p + 12 = 0

=> 7p² - 14p - 6p + 12 = 0

=> 7p(p - 2) - 6(p - 2) = 0

=> (p - 2)(7p - 6) = 0

So :

$\begin{gathered}p = 2 \\ \\ or \\ \\ p = \frac{6}{7} \end{gathered}$

p=2

or

p= 7/6