Question

factorize-7x^2-19x+6​

Answer 1

To factorize this equation, Let's split the middle term,

-19x can be written as (2x - 21x),

Now re writting the equation,

7x² - 21x + 2x - 6

=> Taking 7x common in first 2 terms, and 2 common in last two terms,

=> 7x(x-3) + 2(x-3)

Now taking (x-3) common,

=> (x-3)[7x+2],

This is the required answer,

So therefore the answer is (x-3)[7x+2],

If you need zeroes of the equation, Let the equation be equal to zero,

Now either x-3 = 0, or 7x +2 = 0,

=> Either x = 3 , or x = -2/7,

So zeroes of equation are 3, -2/7,

Answer 2

Answer:

7x²-19x+6.

7x²-21x+2x+6.

-7x(x+3)+2(x+3)

-7x+2)(x+3)

.so x=2/7.

or x= -3