Math, asked by kishormali9038, 9 months ago

Factorize:
8/27 x³ + 1+ 4/3 x² + 2x

Answers

Answered by nikitasingh79
2

The algebraic expression is given as :  8/27 x³ + 1 +  4/3 x² + 2x

We can rewrite the  given expression as :  

= (2/3x)³ + 1³ + 3 × (⅔x) × 1 (2/3x + 1)

In order to factorise the given algebraic expression we use the following Identity - a³ + b³ + 3ab (a + b) = (a + b)³.

Here a = (2/3x) and b = (1) :  

= (2/3x + 1)³

= (2/3x + 1) (2/3x + 1) (2/3x + 1)

Hence, the factorization of an algebraic expression is  (2/3x + 1) (2/3x + 1) (2/3x + 1).

HOPE THIS ANSWER WILL HELP YOU…..

Similar questions :

Factorize:

a³-3a²b+3ab²-b³+8

https://brainly.in/question/15901884

Factorise each of the following:

(i) 8a^3 + b^3 + 12a^2b + 6ab^2

(ii) 8a^3 - b^3 - 12a^2b + 6ab^2

(iii) 27 - 125a^3 - 135a + 225a^2

(iv) 64a^3 - 27b^3 - 144a^2b + 108ab^2

(v) 27p^3 - 1/216 - 9p^2/2 + p/4

https://brainly.in/question/1405684

Answered by Anonymous
0

Answer:

- a³ + b³ + 3ab (a + b) = (a + b)³.

Here a = (2/3x) and b = (1) :  

= (2/3x + 1)³

= (2/3x + 1) (2/3x + 1) (2/3x + 1)

Hence, the factorization of an algebraic

expression is  (2/3x + 1) (2/3x + 1) (2/3x + 1).

Similar questions