factorize
8(p-2q)^2-2pq+4q-1
Answers
Answered by
2
=8(p-2q)^2-2pq+4q-1
=8(p^2+4q^2-4pq) -2pq+4q-1
=8p^2+32p^2-32pq-2pq+4q-1
=8p^2+32p^2-34pq+4q-1
Answered by
1
Step-by-step explanation:
8(p-2q)^2-2pq+4q-1
= 8{p^2+(2q)^2-2×p×2q} -2pq+4q-1
= 8(p^2+4q^2-4pq) - 2pq+4q-1
= 8p^2+32q^2-32pq-2pq+4q-1
= 8p^2+32q^2-3pq+4q-1
Similar questions