Question

Factorize: 8 x^3 + 64 y^3 +125 z^3 -120xyz.

Answer 1

Solution:

/* We know the algebraic

identity :

x³+y³+z³-3xyz = (x+y+z)(x²+y²+z²-xy-yz-zx) */

Now ,

8x³+64y³+125z³-120xyz

= (2x)³+(4y)³+(5z)³-3*2x*4y*5z

=(2x+4y+5z)[(2x)²+(4y)²+(5z)²-(2x)(4y)-(4y)(5z)-(5z)(2x)]

=(2x+4y+5z) [4x²+16y²+25z²-8xy-20yz-10zx]

••••

Answer 2

Answer:

8x³+64y³+125z³-120xyz

= (2x)³+(4y)³+(5z)³-3*2x*4y*5z

=(2x+4y+5z)[(2x)²+(4y)²+(5z)²-(2x)(4y)-(4y)(5z)-(5z)(2x)]

=(2x+4y+5z) [4x²+16y²+25z²-8xy-20yz-10zx]

thank you

Step-by-step explanation: