Question

factorize 8 x cube + 27 y cube + Z cube minus 18 x y z

Answer 1

8x^3=(2x)^3 ---------------a=2x
27y^3=(3y)^3--------------b=3y
and z^3---------------------c=z
18xyz=3(2x)(3y)(z)
since, a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)
so, put the values of a, b and c as in the identity, you will get the answer....
(2x+3y+z)(4x^2+9y^2+z^2-6xy-3yz-2zx)
 All the best  

Answer 2

Step-by-step explanation:

=2x³+3y³+z³-3(2x)(3y)(z)

=2x+3y+z-3(2x)(3y)(z)=(2x+3y+z)

=(2x+3y+z) (4x²+9yz²-6xy-3yz-2xz)