Math, asked by dithynair, 2 months ago

Factorize 81a² - 4b² + 12bc - 9c²

Answers

Answered by Ishikaagarwal1475
1

Answer:

(9a+2b-3c)(9a-2b+3c)

Step-by-step explanation:

81a²-4b²+12bc-9c²

=(9a)²-[(2b)²-2×2b×3c+(3c)²]

using a²-2ab+b²=(a-b)²:-

=(9a)²-(2b-3c)²

now,

using a²-b²=(a+b)(a-b):-

=(9a+2b-3c)(9a-2b+3c)

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