Factorize 81a² - 4b² + 12bc - 9c²
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Answer:
(9a+2b-3c)(9a-2b+3c)
Step-by-step explanation:
81a²-4b²+12bc-9c²
=(9a)²-[(2b)²-2×2b×3c+(3c)²]
using a²-2ab+b²=(a-b)²:-
=(9a)²-(2b-3c)²
now,
using a²-b²=(a+b)(a-b):-
=(9a+2b-3c)(9a-2b+3c)
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