Factorize 81m^4 - (n-m)^4
Answers
Answered by
16
Dear friend,
***The below process may look difficult, but write them down in the notebook to avoid confusion.***
To factorize the expression, we need to apply two algebraic identities,
(i)a^2 - b^2 = (a+b)(a-b)
(ii)(a-b)^2 = a^2 + b^2 - 2×a×b
Let's start factorizing it !
= 81m^4 - (n-m)^4
= [9m^2]^2 - [(n-m)^2]^2
= [9m^2 + (n-m)^2][9m^2 - (n-m)^2]
= [9m^2 + n^2 + m^2 - 2nm][(3m)^2-(n-m)^2]
= (10m^2 + n^2 - 2nm)(3m + n - m)(3m - n + m)
Answer: (10m^2 + n^2 - 2nm)(3m + n - m)(3m - n + m)
Hope it helps !!!
Answered by
2
Answer:
Hey mate here is your answer
Attachments:
Similar questions