Factorize 8a^3b-27b
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Rewrite
8
a
3
as
(
2
a
)
3
.
(
2
a
)
3
−
27
b
3
Rewrite
27
b
3
as
(
3
b
)
3
.
(
2
a
)
3
−
(
3
b
)
3
Since both terms are perfect cubes, factor using the difference of cubes formula,
a
3
−
b
3
=
(
a
−
b
)
(
a
2
+
a
b
+
b
2
)
where
a
=
2
a
and
b
=
3
b
.
(
2
a
−
(
3
b
)
)
(
(
2
a
)
2
+
2
a
(
3
b
)
+
(
3
b
)
2
)
Simplify.
Answered by
0
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