factorize:
8a3 - b3 - 4ax + 2bx
rocky5631:
hii
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19
Answer:
Step-by-step explanation:
a³ - b³ = (a - b)(a² + ab + b²)
8a³ - b³ - 4ax + 2bx
(8a³ - b³) - (4ax - 2bx)
[(2a)³ - b³] - 2x(2a - b)
(2a - b)((2a)² + (2a)(b) + b²) - 2x(2a - b)
(2a - b)(4a² + 2ab + b²) - 2x(2a - b)
(2a - b)(4a² + 2ab + b² - 2x
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