Question

Factorize :

8b^3-1/8b^3-3(2b-1/2b)+27
​

Answer 1

Answer:

Step-by-step explanation:It's simple

4b^2 + 1/b^2= 2 (given)

(2b+1/b)^2= 4b^2 + 1/b^2 + 4

(a+b)^2= a^2 + b^2 +2ab

(2b^+1/b)^2 = 6

(2b+1/b)= -√6,√6

(a+b)^3 = a^3 + b^3 +3ab(a+b)

(2b + 1/b)^3 = 8b^3 + 1/b^3 + 6(2b+1/b)

Put value of (2b+1/b)= +√6

√6^3 = 8b^3 + 1/b^3 + 6(√6)

6√6= 8b^3 + 1/b^3 + 6√6

(8b^3 + 1/b^3) = 0

If you take value of (2b+1/b) as -√6

-6√6= 8b^3+1/b^3-6√6

(8b^3+1/b^3) = 0

In both the cases answer is 0