Question

factorize
8x^3+27y^3​

Answer 1

Answer:

$8 {x}^{3} + 27 {y}^{3} \\ {(2x)}^{3} + {(3y)}^{3} \\ (2x + 3y)( {(2x)}^{2} - (2x \times 3y) + ( {3y)}^{2} ) \\ (2x + 3y)(4 {x}^{2} - 6x y + 9 {y}^{2} )$

Answer 2

Step-by-step explanation:

8x^3+27y^3=(2x)^3 +(3y)^3

=(2x+3y)((2x)^2-(2x)(3y)+(3y)^2)

=(2x+3y)((4x^2-6xy+9y^2)