factorize 8x^3-(2x-3y)^3
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2
Answer:
8x³-(2x-3y)³
= (2x)³-(2x-3y)³
= (2x-2x+3y)(4x²+4x²-6xy+4x²+12xy+9y²)
= (3y)(12x²+6xy+9y²)
Answered by
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Answer:
a³ - b³ = (a-b)(a²+ab+b²) 8x³-(2x-3y)³ =(2x- (2x-3y)((2x)²+(2x)(2x-3y)+(2x-3y)²). =3y(4x²+4x-4xy+4x²+9y²-12xy)
=3y(8x²-16xy+4x+9y²)
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