Math, asked by Anjana2005, 10 months ago

Factorize 9(2a-b)^2-4 (2a-b)-13

Answers

Answered by mhanifa
1

Answer:

(6a-2b+5/9)*(6a-2b-17/9)

Step-by-step explanation:

9(2a-b)^2-4 (2a-b)-13=

(3*(2a-b))^2-2*3*2/3* (2a-b)+ (2/3)^2-(13+4/9)=

(3*(2a-b)- 2/3)^2- 13 4/9=

(6a-2b-2/3)^2- 121/9=

(6a-2b-2/3)^2- (11/9)^2=

(6a-2b-2/3+11/9)*(6a-2b-2/3-11/9)=

(6a-2b+5/9)*(6a-2b-17/9)

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