factorize:9(x+y)^2-x^2
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Answer:
9(x+y)^2-x^2
= {3 (x+y)}^2 -(x)^2
now, it is in the form of a^2 - b^2
so, by using that identity
{3 (x+y) -x}{3(x+y) + x}
= (3x + 3y - x) (3x + 3y +x)
= (2x + 3y )( 4x + 3y)
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