Math, asked by anjali81, 1 year ago

factorize​ ,9a2_6abc+c2

Answers

Answered by Anonymous
0
9a²-6ac+c²

(3a)²-2(3a)(c)+(c)² [(a²-2ab+b²=(a-b)²]

=(3a-c)² ANSWER...

anjali81: thanks
Anonymous: my pleasure :-))
Answered by Anonymous
2
hi guys!!
======
Given,
9a^2- 6ac+(c)^2
=(3a)^2-2.3a.c+(c)^2
=(3a-c)^2
=(3a-c) (3a-c)
>>>>>>>>>>>>>>>>>>>>>>

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