factorize ,9a2_6abc+c2
Answers
Answered by
0
9a²-6ac+c²
(3a)²-2(3a)(c)+(c)² [(a²-2ab+b²=(a-b)²]
=(3a-c)² ANSWER...
(3a)²-2(3a)(c)+(c)² [(a²-2ab+b²=(a-b)²]
=(3a-c)² ANSWER...
anjali81:
thanks
my pleasure :-))
Answered by
2
hi guys!!
======
Given,
9a^2- 6ac+(c)^2
=(3a)^2-2.3a.c+(c)^2
=(3a-c)^2
=(3a-c) (3a-c)
>>>>>>>>>>>>>>>>>>>>>>
======
Given,
9a^2- 6ac+(c)^2
=(3a)^2-2.3a.c+(c)^2
=(3a-c)^2
=(3a-c) (3a-c)
>>>>>>>>>>>>>>>>>>>>>>
well done andrew!!
xD proud of u
see inbox mr.chocolate XD
Similar questions