factorize 9x^2-6b^2x-(a^4-b^4)=0
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Correct Question :
factorize 9x²-6b²x-a⁴-b⁴ = 0.
AnsWer :
- x = b² - a² /3
- x = b² + a² /3.
SolutioN :
factorize the middle term.
→ 9x²-6b²x-a⁴-b⁴ = 0.
→ 9x² - 6b²x - a⁴ - b⁴ = 0.
→ ( 3x )² - 2( 3x )( b² ) - a⁴ + ( b² )² = 0.
→ ( 3x - b² )² - a⁴ = 0.
→ ( 3x - b² )² - ( a² )² = 0.
→ ( 3x - b² + a² )( 3x - b² - a² ) = 0.
★ Either,
3x - b² + a² = 0.
→ 3x = b² - a²
→ x = b² - a² /3
★ Or,
→ 3x - b² - a² = 0.
→ 3x = b² + a² .
→ x = b² + a² /3.
Some Formula :
- ( a + b )( a - b ) = a² - b².
- ( a + b )² = a² + b² + 2ab.
- ( a - b )² = a² + b² - 2ab.
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