Question

factorize 9x²-6b²x-(a⁴-b⁴)=0

Answer 1

Solution :

9x² - 6b²x - ( a⁴ - b⁴ ) = 0

=> 9x² - 6b²x - ( a²+b² )( a² - b² ) = 0

=>9x²-3(a²+b²)x+3(a²-b²)x-(a²+b²)(a²-b²)=0

=> 3x[3x-(a²+b²)]+(a²-b²)[3x-(a²+b²)]=0

=> [3x - (a²+b²)][ 3x + ( a² - b² ) ] = 0

=> [3x - (a²+b²)]=0 or [3x+(a²-b²)] = 0

=> x = ( a² + b² )/3 or x = ( b² - a² )/3

••••

Answer 2

Answer:

Step-by-step explanation:Solution : Hey mate, here you go

9x² - 6b²x - ( a⁴ - b⁴ ) = 0

=> 9x² - 6b²x - ( a²+b² )( a² - b² ) = 0

=>9x²-3(a²+b²)x+3(a²-b²)x-(a²+b²)(a²-b²)=0

=> 3x[3x-(a²+b²)]+(a²-b²)[3x-(a²+b²)]=0

=> [3x - (a²+b²)][ 3x + ( a² - b² ) ] = 0

=> [3x - (a²+b²)]=0 or [3x+(a²-b²)] = 0

=> x = ( a² + b² )/3 or x = ( b² - a² )/3

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