Question

factorize a^2 - 10a+ 21

Answer 1

Answer:

${a}^{2} - 10a + 21 \\ {a}^{2} - (7 + 3)a + 21 \\ {a}^{2} - 7a - 3a + 21 \\ a(a - 7) - 3(a - 7) \\ (a - 7)(a - 3) \\ a = 7 \\ a = 3 \\ hope \: it \: will \: help \: you$

Answer 2

a^2-10a+21=0

a^2--7a-3a+21=0

a(a-7)-3(a-7)=0

(a-7)(a-3)=0

(a-7)=0 or (a-3)=0

a=7 or a=3