Question

factorize: a^2 + b^2 - 2ba + 2bc - 2ca

Answer 1

a^2 + b^2 - 2ba + 2bc - 2ca

(a - b)^2 + 2bc - 2ca

(a - b)^2 + 2c(b - a)

(a -b)^2 - 2c(a - b)

(a - b)(a - b - 2c)





i hope this will help you

(-:

Answer 2

Heya ✋

Let see your answer !!!!!

$a ^{2} + b ^{2} - 2ba + 2bc - 2ca \\ \\ = (a - b) ^{2} - 2ca + 2bc \\ \\ = (a - b) ^{2} - 2c(a - b) \\ \\ = (a - b)(a - b - 2c)$








Thanks :)))))