factorize ( a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3
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Answer:
Step-by-step explanation:
(a²-b²)³+(b²-c²)³+(c²-a²)³
if x+y+z=0, then x³+y³+z³=3xyz
let (a²-b²)=x , (b²-c²)=y , (c²-a²)=z
so, now
(a²-b²)+(b²-c²)+(c²-a²)=0
a²-b²+b²-c²+c²-a²=0
0=0
so (a²-b²)+(b²-c²)+(c²-a²)=0
⇒(a²-b²)³+(b²-c²)³+(c²-a²)³=3(a²-b²)(b²-c²)(c²-a²)
hope it helps
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