Question

Factorize- a^2 x^2 + (ax^2+1)x+a

Answer 1

Your Answer:

$\tt a^{2} x^{2}+(ax^{2}+1)x+a \\\\ \tt Solving \: brackets\: first\\\\ \tt = a^{2}x^{2}+ax^{3}+x+a\\\\= ax^{2}(a+x)+1(x+a)\\\\ \tt =(x+a)(ax^{2}+1)$

So the factors are

$\tt =(x+a)(ax^{2}+1)$

Concepts Used:

• Quadratic Formula
• Mathematical Solvings
• Algebra
• Opening of Brackets

Answer 2

* Factorization *

__________________________

a²x²+(ax²+1)x+a

→ As a BODMAS Rule

→ a²x²+ax³+x+a..... (By solving the brackets first)

→ ax²(a+x) +1(x+a) .... (By taking ax² as a common)

→(ax²+1)(a+x)

Therefore,

The factors are (ax²+1)(a+x).