Math, asked by bojendrakumar, 11 months ago

factorize:a^24-b^24​

Answers

Answered by hadigaaranaruto
0

Answer:

(a^12-b^12)(a^12+b^12)

Answered by Fifth
0

a^{24}-b^{24}

a^{12}^2-b^{12}^2

(a^{12}+b^{12})     (a^{12}-b^{12})

((a^4)^3+(b^4)^3) (a^{12}-b^{12})

(a^4+b^4)(a^8-a^4b^4+b^8 ) (a^{12}-b^{12})

(a^4+b^4)(a^8-a^4b^4+b^8 ) (a^6)^2 - (b^6)^2

(a^4+b^4)(a^8-a^4b^4+b^8 ) (a^6+b^6) (a^6-b^6)

(a^4+b^4)(a^8-a^4b^4+b^8 ) (a^2+b^2)(a^4-a^2b^2+b^4)(a^6-b^6)

(a^4+b^4)(a^8-a^4b^4+b^8 ) (a^2+b^2)(a^4-a^2b^2+b^4) (a^3+b^3)(a^3-b^3)

(a^4+b^4)(a^8-a^4b^4+b^8 ) (a^2+b^2)(a^4-a^2b^2+b^4) (a+b)(a^2-ab+b^2)(a-b)(a^2+ab+b^2)

HOPE THIS HELPS ^_^

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