Question

factorize a^2b^4c^6-1
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Answer 1

Answer:

The Correct Answer is

$(ab {}^{2} c {}^{3} - 1)(ab {}^{2} c {}^{3} + 1)$

Step-by-step explanation:

Given,

$a {}^{2} b {}^{4} c {}^{6} - 1\\ = a {}^{2} b {}^{2 \times 2} c {}^{2 \times 3} - 1 {}^{2} \\ =a {}^{2} \times (b {}^{2} ) {}^{2} \times (c {}^{3} ) {}^{2} - 1 {}^{2} \\ = (ab {}^{2} c {}^{3} ) {}^{2} - 1 {}^{2} \\ = (ab {}^{2} c {}^{3 } - 1) \times (ab {}^{2} c {}^{3 } + 1)$

Hope this will help you!

Answer 2

Answer:

Step-by-step explanation:

Hope this will help you!