Question

Factorize a^2bx+2a^2cx-2aby-4acy+bz+2cz

Answer 1

here is the solution of the given problem

Answer 2

Answer:

Step-by-step explanation:

Factorization:

                        It is defined as the splitting up of a thing into parts that, when multiplied together, make up the original thing.Factorization is the division of a number into its factors or divisors.The factorization of the integer 12, for instance, might appear as 3 times 4.

When you reduce a number to its prime factors, you can further break that down using prime factorization.In this instance, 12 can be factored as 3 x 2 x 2.The word factor, which has a mathematical definition since the 1600s, is the root of the phrase factorization.

Solution:

                  a²bx+2a²cx-2aby-4acy+bz+2cz

                   = a²x(b+2c)-2ay(b+2c)+z(b+2c)

                   Taking b+2c is common

                   = (b+2c)(a²x-2ay+z)

So, the  factor of a²bx+2a²cx-2aby-4acy+bz+2cz is (b+2c)(a²x-2ay+z)

#SPJ2