Question

factorize: a 3 -1/a 3 -2a+2/a

Answer 1

Answer:

Step-by-step explanation:

Substituting 1/a as b

Taking first term a^3-b^3=(a-b)(a^2+ab+b^2)

Second term -2(a-b)

(a-b) (a^2+ab+b^2)-2(a-b)

a-b is common

So (a-b) (a^2+ab+b^2)-2(1)

Substituting b =1/a

(a-1/a)(a^2+a*1/a+1/a^2)-2

(a-1/a) (a^2+1/a^2+1)-2

(a-1/a) (a^2+1/a^2-1)

This is the ans.

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Answer 2

Answer:

(a-1/a) (a2+1+1/a2) -2(a-1/a)

(a-1/a) (a2+1+/a2-2)

(a-1/a) (a2+1/a2-1)