Math, asked by kittytoon556, 1 month ago

Factorize: a 3 – 2√2 b 3​

Answers

Answered by Anonymous
20

Answer:

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Answered by ummesaima
0

Answer:

We know the identity a3−b3=(a−b)(a2+b2+ab)

Using the above identity, the equation 1−x3 can be factorised as follows:

a3−22b3=(a)3−(2b)3=(a−2b)[(a)2+(2b)2+(a×2b)]=(a−2b)(a2+2b2+2ab) 

Hence, a3−22b3=(a−2b)(a2+2b2+2ab)

Step-by-step explanation:

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