Question

Factorize: a^3+27b^3+8c^3+18abc

Answer 1

i hope this will usful to u

Answer 2

Given  a3+27b3+8c3-18abc
= (a3+(3b)3+(2c)3-3*a*3b*2c)   // use of the identity (a3+b3+c3-3abc) = (a+b+c) (a2+b2+c2-ab-bc-ca)  //
= (a+3b+2c) (a2+(3b)2+(2c)2-a*3b-3b*2c-2c*a)    // a=a,b= 3b, c= 2c  //
= (a+3b+2c) (a2+9b2+4c2-3ab-6bc-2ca)