factorize
a^3+27b^3+8c^3-18abc
solve fast ..................
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(a)³+(3b)³+(2c)³-3(a)(3b)(2c)
using formula a³+b³+c³-3abc = (a+b+c)(a²+b²+ c²-ab-bc-ca)
(a+3b+2c)(a²+9b²+4c²-3ab-6bc-2ac)
hope this helps
using formula a³+b³+c³-3abc = (a+b+c)(a²+b²+ c²-ab-bc-ca)
(a+3b+2c)(a²+9b²+4c²-3ab-6bc-2ac)
hope this helps
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