Question

factorize a^3+b^3-8c^3+6abc

Answer 1

Using identity x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx)  

Which gives

a3−b3+8c3−6abc=(a−b+2c)(a2+b2+4c2+ab+2bc−2ca)

Answer 2

Answer:

a^3+b^3+8c^3-6abc

Step-by-step explanation:

yes