Factorize (a+3b).(2a +b) – (2a+b).(a+b) + (3a+2b)^2
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Step by step explanation
Now , expanding the terms :
=>a(2a+b)+3b(2a+b)-[2a(a+b)+b(a+b)]+(3a+2b)²
Identity used here :
✰(a+b)²=a²+b²+2ab
=>2a²+ab+3ab+3b²-[2a²+2ab+ab+b²]+(3a)²+(2b)²+2(3a)(2b)
=>Now ,removing the brackets and expanding the terms :
=>2a²+ab+3ab+3b²-2a²-2ab-ab-b²+9a²+4b²+12ab
=>Rearranging the terms and make like terms together:
=>2a²-2a²+ab-ab+3ab-2ab+3b²-b²+9a²+4b²+12ab
2a² will be cancelled as plus minus = minus.Similarly, ab will be cancelled.
=>3ab-2ab+3b²-b²+9a²+4b²+12ab
=>ab+2b²+9a²+4b²+12ab
=>9a²+2b²+4b²+ab+12ab
=>9a²+6b²+13ab
Further solve : we can take 3 as common as 9 and 6 are multiples of 3
=>3(3a²+2b²)+13ab
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