Question

factorize
a (a-2b-c) +2bc

Answer 1

Given : a(a−2b−c)+2bc

By multiplying the terms

a(a−2b−c)+2bc =a

2

−2ab−ac+2bc

By taking the common terms out

a(a−2b−c)+2bc =a(a−2b)−c(a−2b)

So we get,

a(a−2b−c)+2bc =(a−c)(a−2b)

Answer 2

Step-by-step explanation:

Given : a(a−2b−c)+2bc

By multiplying the terms

a(a−2b−c)+2bc =a

2

−2ab−ac+2bc

By taking the common terms out

a(a−2b−c)+2bc =a(a−2b)−c(a−2b)

So we get,

a(a−2b−c)+2bc =(a−c)(a−2b)

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