Factorize: (a-b) 3 + (b-c) 3 +(c-a)3
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(a-b)3 + (b-c)3 + (c-a)3
Let,
a = a-b ; b = b-c; c = c-a
a+b+c = (a-b)+ (b-c) + ( c-a) = 0
therefore,
a3+b3+c3= 3abc
=3(a-b)(b-c)(c-a)
Let,
a = a-b ; b = b-c; c = c-a
a+b+c = (a-b)+ (b-c) + ( c-a) = 0
therefore,
a3+b3+c3= 3abc
=3(a-b)(b-c)(c-a)
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