factorize (a/b)x^2+(a/b+c/d)x+c/d, where b & d not equal to zero
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(a/b)x^2 + (a/b)x+(c/d)x+c/d
= (a/b)x[x+1]+c/d[x+1]
=(x+1)[(a/b)x+c/d]
= (a/b)x[x+1]+c/d[x+1]
=(x+1)[(a/b)x+c/d]
mysticd:
ur welcome
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(a/b)x^2 + (a/b)x+(c/d)x+c/d
= (a/b)x[x+1]+c/d[x+1]
=(x+1)[(a/b)x+c/d]
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