Math, asked by bhattisingh111, 1 year ago

factorize (a/b)x^2+(a/b+c/d)x+c/d, where b & d not equal to zero

Answers

Answered by mysticd
1
(a/b)x^2 + (a/b)x+(c/d)x+c/d

= (a/b)x[x+1]+c/d[x+1]
=(x+1)[(a/b)x+c/d]

mysticd: ur welcome
Answered by Anonymous
0

(a/b)x^2 + (a/b)x+(c/d)x+c/d

= (a/b)x[x+1]+c/d[x+1]

=(x+1)[(a/b)x+c/d]

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