.:-Factorize:- (a)X - (y+2) (b) 1+ 2xy-(x +y)
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Answer:
The factor of 1−x 2
−2xy−y 2
is
Rearranging the terms
⇒ 1−(x 2 +2xy+y 2 )
⇒ −1(x+y) 2
[∵ (x+y) 2
=x 2 +2xy+y 2 ]
⇒ (1−(x+y) 2 )
⇒ (1) 2
=(x+y) 2
[∵(1)2 =1]
Using a 2 −b 2
=(a+b)(a−b)
⇒ (1−(x+y))(1+(x+y))
⇒ (1−x−y)(1+x+y)
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