Math, asked by prabhasoni854, 7 months ago

Factorize:
(a) x3-3x-1+3/x-1/x3​

Answers

Answered by pulakmath007
12

SOLUTION

TO FACTORISE

 \displaystyle \sf{ {x}^{3}   - 3x - 1 +  \frac{3}{x}  -  \frac{1}{ {x}^{3} } \: }

EVALUATION

 \displaystyle \sf{ {x}^{3}   - 3x - 1 +  \frac{3}{x}  -  \frac{1}{ {x}^{3} } \: }

 =  \displaystyle \sf{ {x}^{3}   - 3x  +  \frac{3}{x}  -  \frac{1}{ {x}^{3} } - 1 \: }

 =  \displaystyle \sf{ {(x)}^{3}   - 3. {x}^{2} . \frac{1}{x}  +  {3}.{x} . \frac{1}{ {x}^{2} }  -  { \bigg(  \frac{1}{x} \bigg)}^{3} - 1 \: }

 =  \displaystyle \sf{  { \bigg(x -   \frac{1}{x} \bigg)}^{3} -  {(1)}^{3}  \: }

 =  \displaystyle \sf{ \bigg(x -  \frac{1}{x}  - 1 \bigg)   \Bigg[{ \bigg(x -   \frac{1}{x} \bigg)}^{2}  +\bigg(x -   \frac{1}{x} \bigg) +    {(1)}^{2}  \Bigg]  }

 =  \displaystyle \sf{ \bigg(x -  \frac{1}{x}  - 1 \bigg)   \Bigg[{ \bigg(x -   \frac{1}{x} \bigg)}^{2}  +\bigg(x -   \frac{1}{x} \bigg) +    1 \Bigg]  }

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