Question

Factorize (a²- 1) (6²1) + 4ab​

Answer 1

Answer:

(a2−1)(b2−1)+4ab

=a2b2−a2−b2+1+2ab+2ab

=(ab)2+2(ab)(1)+12−(a2−2ab+b2)

=(ab+1)2−(a−b)2

=(ab+1+a−b)(ab+1−a+b)

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Step-by-step explanation:

Answer 2

Answer:

a2−1)(b2−1)+4ab

=a2b2−a2−b2+1+2ab+2ab

=(ab)2+2(ab)(1)+12−(a2−2ab+b2)

=(ab+1)2−(a−b)2

=(ab+1+a−b)(ab+1−a+b

I hope its help you.....