Factorize [a²+1]b²-b⁴-a2
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Answer:
(a^2+1)b^2-b^4-a^2
=a^2b^2+b^2-b^4-a^2
=a^2b^2-a^2-b^4+b^2
=a^2(b^2-1)-b^2(b^2-1)
=(b^2-1)(a^2-b^2)
=(b+1)(b-1)(a+b)(a-b)
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