Question

factorize a²+4b²+25c²-4ab+20bc-10ca​

Answer 1

Step-by-step explanation:

ANSWER

4a

2

+b

2

+25c

2

−4ab−10bc+20ca

=(2a)

2

+(−b)

2

+(5c)

2

+2×2a×(−b)+2×(−b)×5c+2×5c×2a

Using, (a+b+c)

2

=a

2

+b

2

+c

2

+2ab+2bc+2ca

=(2a−b+5c)

2

=(2a−b+5c)(2a−b+5c)

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Answer 2

Step-by-step explanation:

a²+4b²+25c²-4ab+20bc-10ca

here,

a²+(2b)²+(5c)²-2*a*2b+2*2b*5c+2*a*5c

(-a+2b+5c)²

because,

a² + b² + c²+ 2 ab + 2 bc + 2ca=(a+b+c)²

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