Factorize: a²+4b²+9c²+4ab+12bc+6ca
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Answer:
(a + 2b + 3c) ^2
Step-by-step explanation:
by using identity
a^2 + b^2 + c^2 + 2ab + 2bc + 2ca
a^2 + 2b^2 + 3c^2 + 2 * a * 2b + 2 * 2b * 3c + 2 * 3c + a
which gives
(a + 2b + 3c) ^2
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