Question

factorize :
a² + 5a - 104​

Answer 1

Step-by-step explanation:

${a}^{2} + 5a - 104$

${a}^{2} + 13a - 8a - 104$

$a(a + 13) - 8(a + 13)$

$(a - 8)(a + 13)$

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Answer 2

Answer:

ok let me help you

Step-by-step explanation:

In the given polynomial: a^2 + 5a-104

The first term is a^2  and its coefficient is 1.

The middle term is 5a and its coefficient is 5.

The last term is a constant term −104.

Multiply the coefficient of the first term by the constant 1*−104=−104.

We now find the factor of −104 whose sum equals the coefficient of the middle term, which is 5 and then factorize the polynomial a  ^2 +5a−104 as shown below:

a  ^2  +5a−104

= a  ^2 +13a−8a−104

=a(a+13)−8(a+13)

=(a−8)(a+13)

Hence, a  ^2  +5a−104=(a−8)(a+13).

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