factorize : a2 (b+c) – (b+c)3
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- (b+c)(a²-(b+c)²)
- Let b+c += x
- ∴ a²(b+c) - (b+c)a³ = a²x - x³
- => x(a²-x²)
- ∵ x = b+c
- ∴ a²(b+c) - (b+c)³
- => (b+c)(a² - (b+c)²)
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