Question

Factorize a2 + b2 + 2( ab+bc+ca )​

Answer 1

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a^2 + b^2 + 2ab + 2bc + 2ca

As we know, p^2 + q^2 + 2pq = (p + q)^2

We get,

= ( a+b)^2 + 2bc + 2ca

= ( a+b)^2 + 2c( b + a )

Or

( a+b)^2 + 2c( a + b )

Take ( a + b ) as common factor;

= ( a + b )( a + b + 2c )

Therefore,

a^2 + b^2 + 2ab + 2bc + 2ca = ( a + b )( a + b + 2c )

Answer 2

a²+b²+2(ab+bc+ca)

= a²+b²+2ab+2(bc+ca)

= (a+b)²+2c(b+a)

= (a+b)²+2c(a+b)

= (a+b)(a+b+2c)

Beainliest Please •••♪